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0.125x^2+2.5x-3=0
a = 0.125; b = 2.5; c = -3;
Δ = b2-4ac
Δ = 2.52-4·0.125·(-3)
Δ = 7.75
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.5)-\sqrt{7.75}}{2*0.125}=\frac{-2.5-\sqrt{7.75}}{0.25} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.5)+\sqrt{7.75}}{2*0.125}=\frac{-2.5+\sqrt{7.75}}{0.25} $
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